Mai, Boris, and Hong have a total of $62 in their wallets. Mai has $10 less than Hong. Boris has 2 times what Hong has. How much does each have?
Start with naming names:
Let the amount of money in:
Mai's wallet = M
Boris's wallet = B
Hong's wallet = H
Then:
Mai, Boris, and Hong have a total of $62 → M + B + H = 62 ........................................(1)
Mai has $10 less than Hong → M + 10 = H .............................................................(2)
Boris has 2 times what Hong has → B = 2 * H .........................................................(3)
3 equations and 3 unknowns - solve using your favorite method.
Since you posted this to "Arithmetic", it is safe to assume that you've not yet taken pre-algebra yet, so you don't know anything about variables or solving systems of equations.Mai, Boris, and Hong have a total of $62 in their wallets. Mai has $10 less than Hong. Boris has 2 times what Hong has. How much does each have?
Hong:
*----*
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*----*
Since B = 2*H, substitute 2*H in for B in the first equation. Thus, M + 2*H + H = 62, or M + 3*H = 62.
Now, subtract 10 from H to solve or M in the second equation. M = H - 10. Substitute (H - 10) in for M in the first equation. This gives you 4H + 10 = 62, which is a simple two-step equation to solve. When all is said and done, you should have $13 for Hong, $23 for Mai, and $26 for Boris.
This is not correct! Mai has $10 LESS than Hong not MORE!
Correct answer is:
M + B + H = 62
We know B equals ( 2H ) and M equals ( H-10 ) so:
H - 10 + 2H + H = 62
4H - 10 = 62
4H = 62 +10
4H = 72
H = 72/4 =18
So Hong has $18
Since Boris has 2 times what Hong has,
B = 18 x 2 = $36
So Boris has $36
Since Mai has $10 less than Hong,
M= 18 - 10 = $8
So Mai has $8
Cheers :cool:!
Thank you for showing me the error. I admit that I was a little sleepy when I worked this problem out...those pesky signs got me again.