I need help solving polynomial equations!

SuperstarBarbie

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Joined
Apr 10, 2010
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I have been surfing the internet all morning, and I abosolutely cannot! find anyone to help me solve this problem. It is x^3-5x^2+3x+9=0. I have not been able to pass this step. I have been staring at this equation for an hour, and I still can't figure it out. All I know is that it is not factorable, and you obviously cannot use the quadratic equation on this one. If you can help, it will be greatly appreciated. Thanks!
?,
Superstar Barbie!
 
You might try dividing the given cubic by a binomial. You know that for it to divide exactly, the constant term of the binomial will have to divide exactly into +9. That leaves you with the following as candidates.
x+1
x-1
x+3
x-3
x+9
x-9
You might try dividing your cubic by each of these to see if one of them can be a factor. If so, you might end up with a second degree trinomial that can be factored further. I happen to disagree with your statement that it can't be factored. I got it to factor into the product of three binomials.
 
To save you some time: (x^2 - 2x - 3) is result of division by (x - 3); OK?
 
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