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Guest
Guest
Well we are doing this free response paper and I was able to finish the first one correctly, I think, but I need help on the 2nd problem:
Consider the curve given by the equation y^3 + 3x^2(y) + 13=0
(a) Find dy/dx.
(b) Write an equation for the line tangent ot the curve at the point (2, -1).
(c) Find the minimum y-coordinate of any point on the curve. Justify your answer.
I worked on finding the derivative of the function but I got a bit confused because it said dy/dx. This means the same thing as y' right?
If so what I did was that I first used the quotient rule on y^3 and turned it into 3y^2
Then I used the product rule on 3x^2(y) and got 3x^2 +6xy
Did I do this right?
Please Respond and Thank you in advance
With Respect,
Carlos
Consider the curve given by the equation y^3 + 3x^2(y) + 13=0
(a) Find dy/dx.
(b) Write an equation for the line tangent ot the curve at the point (2, -1).
(c) Find the minimum y-coordinate of any point on the curve. Justify your answer.
I worked on finding the derivative of the function but I got a bit confused because it said dy/dx. This means the same thing as y' right?
If so what I did was that I first used the quotient rule on y^3 and turned it into 3y^2
Then I used the product rule on 3x^2(y) and got 3x^2 +6xy
Did I do this right?
Please Respond and Thank you in advance
With Respect,
Carlos