wheretheoppsat
New member
- Joined
- May 3, 2021
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- 1
please help me solve this equation: x = 50 000 log (9) (10 601.8191) + 20 000
Are you supposed to ask for help during exam??please help me solve this equation: x = 50 000 log (9) (10 601.8191) + 20 000
We haven’t considered it might be a course on worst questions to cheat in an exam (unless it’s a non calculator one, but then you’re on your phone anyway!). HallsofIvy you have more patience and good will than me.You're in the exam? Is this a course in "Getting other people to do your work for you"?
Also, what do you mean by "solve this equation". Basically the equation already says "x= " a single number and that is, to me, what "solving an equation" means!
Is the problem how that number is written? It is "50 000 log (9) (10 601.8191) + 20 000". Do you know what log(9)(10601.8181) means? Surely it is not multiplying by 50000 or addint 20000 that is the problem!
You need to know that \(\displaystyle log_a(b)= \frac{log(b)}{log(a)}\) where the "log" on the right is to whatever base you want. I am sure your calculator (or at any rate a calculator you would want for a course like this) has the "natural logarithm", ln, key and possibly a "common logarithm", base 10 key. Either of those will work.