I need help graphing this one

locomocoso

New member
Joined
Oct 5, 2005
Messages
7
I need to graph log base 5 at x + log base 3 at x =1
I don't know how to write that on here to look better. I can't figure out how to convert both logs to the same base. I have the formula but can't figure it out with 3 and 5. Please help.
 
Hello, locomocoso1

Could you state the original problem?

I need to graph log base 5 at x + log base 3 at x =1
I'll take a wild guess . . .

Maybe it is : .f(x) .= .log<sub>5</sub>x + log<sub>3</sub>x . . . at x = 1

If so, they are asking for a <u>point</u>.

. . f(1) .= .log<sub>5</sub>(1) + log<sub>3</sub>(1) .= .0 + 0 .= .0

Plot the point (1,0).
 
how do you write those subscripts?
ok, the original problem was not written as a function. it was not at x=1. log base5 at x + log base3 at x, that quantity equals 1.

you had it right except for the f(x) and x=1.
 
You can type x<sub>5</sub> by (one "word", no spaces)
x
<
sub
>
5
<
/sub
>

You can type superscripts (exponents) with the same "word" but sup instead of sub

You can make things easier by using LOTS of ()s. You can't use too many. Any function should use them to show where it ends.
sqrt x + 5 needs
sqrt(x)+5 or
sqrt(x+5)
Most fractions need them
x+2/x-2 needs
x+(2/x)-2 or
x+(2/(x-2)) or
(x+2)/(x-2)
Yes, PEMDAS says you don't need all of them but more people don't use them when they are needed than mean what they typed.

Are you saying
log<sub>5</sub>(x)+log<sub>3</sub>(x)=1
It doesn't look like a graphing problem that way. The log<sub>5</sub>(x)+log<sub>3</sub>(x) could be graphed, then evaulated for at y=1 (or f(x)=1. Same thing.) but I wouldn't say it equals 1
If not please retype the whole problem with these rules in mind.
 
I am so sorry

i had written down the wrong page number, no wonder it didn't make any sense to me. you were completely right about that one, it was a point. thanks again, and thank for the advice on sub and super scripts.
 
Top