I NEED HELP ASAP!!!!!!!!!!!!!!11

P

Professor Awesome

New member
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Nov 13, 2005
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11
here are the problems I need to solve. I need them really fast. Its due tomorrow and being graded and I have know idea what I'm doing.

i need to show work too

 
A little effort to show what you are doing will help guide you....but for #3 to start you off.

bring the top line to a common base ...

( a(a-b) + b (a+b) ) / ( (a+b) (a-b) )


same for the bottom line

( b(a-b) - a(a+b) ) / ( (a+b) (a-b) )

expand each of these and cancel out to find

= -1
 
For anybody who can't see the graphic, the exercises are as follows:

. . . . .Simplify:

. . . . .\(\displaystyle \large{1)\mbox{ }\frac{x^2\mbox{ }-\mbox{ }2xy\mbox{ }+\mbox{ }xy\mbox{ }-\mbox{ }2y^2}{3xy\mbox{ }+\mbox{ }3y^2\mbox{ }-\mbox{ }x^2\mbox{ }-\mbox{ }xy}}\)

. . . . .\(\displaystyle \large{2)\mbox{ }\frac{\frac{a}{a\mbox{ }+\mbox{ }b}\mbox{ }+\mbox{ }\frac{b}{a\mbox{ }-\mbox{ }b}}{\frac{b}{a\mbox{ }+\mbox{ }b}\mbox{ }-\mbox{ }\frac{a}{a\mbox{ }-\mbox{ }b}}}\)

. . . . .\(\displaystyle \large{3)\mbox{ }1\mbox{ }-\mbox{ }\frac{1}{1\mbox{ }+\mbox{ }\frac{1}{x\mbox{ }-\mbox{ }\frac{1}{x}}}}\)

To the poster:

1) Factor "by grouping", and cancel common factors, if any.

2) One method would be to multiply through, top and bottom, by the overall common denominator of (a + b)(a - b). Then simplify the result.

3) Work from the bottom up.

Eliz.
 
Professor Awesome said:
I have no idea where to start or what to do.
Click to expand...
So you haven't learned how to factor yet...?

Eliz.
 
So... you're asking for lessons on the various aspects of factoring polynomial expressions...? (This would take a week or two in the classroom, but we can probably find some online lessons that you could work through over a couple of days, if this is what you're asking for.)

Thank you.

Eliz.
 
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