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i need algebra 2 help ASAP!!!
- Thread starter quana
- Start date
solve each equation for y. a(y+c)=b(y-c) and 3y-yz=2z
Solving for y just means to get y by itself on one side of the equation.
For the first one, a(y+c)=b(y-c), distribute (multiply out) on both sides of the equation. Next, get all your y terms on one side and everything else on the other by using addition or subtraction. Factor y out of the two terms that have y as factors. Finally, divide both sides of the equation by (a - b, if you did it right) to get y by itself.
The second one, 3y-yz=2z, is simpler. Factor y out of the two terms that have y as factors. Finally, divide both sides of the equation by (3 - z) to get y by itself.
can u do an example problem???
Solving for y just means to get y by itself on one side of the equation.
For the first one, a(y+c)=b(y-c), distribute (multiply out) on both sides of the equation. Next, get all your y terms on one side and everything else on the other by using addition or subtraction. Factor y out of the two terms that have y as factors. Finally, divide both sides of the equation by (a - b, if you did it right) to get y by itself.
The second one, 3y-yz=2z, is simpler. Factor y out of the two terms that have y as factors. Finally, divide both sides of the equation by (3 - z) to get y by itself.
Example:
4(a +b) = b(a – 2b); Solve for “a”.
4a + 4b = ba – 2b^2
Subtract 4b from both sides:
4a = ba – 2b^2 – 4b
Subtract ba from both sides:
4a – ba = -2b^2 – 4b
Now we have gotten all the terms with “a” on the left hand side and all other terms on the right hand side. Time to factor out "a":
4a – ba = -2b^2 – 4b
a(4 – b) = -2b^2 – 4b
Finally, divide both sides by (4 – b) so that “a” is left by itself:
a = (-2b^2 – 4b)/(4 – b)
4(a +b) = b(a – 2b); Solve for “a”.
4a + 4b = ba – 2b^2
Subtract 4b from both sides:
4a = ba – 2b^2 – 4b
Subtract ba from both sides:
4a – ba = -2b^2 – 4b
Now we have gotten all the terms with “a” on the left hand side and all other terms on the right hand side. Time to factor out "a":
4a – ba = -2b^2 – 4b
a(4 – b) = -2b^2 – 4b
Finally, divide both sides by (4 – b) so that “a” is left by itself:
a = (-2b^2 – 4b)/(4 – b)