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I need a little hand please with -4x + 3y = -6
- Thread starter maurize
- Start date
Re: I need a little hand please.
-4x +3y= -6 says that there are two numbers, one named x and the other named y, such that if we multiply the first one (x) by a negative 4 and add that result to three times the second one (y), we get a sum of a negative 6.
-4x +3y= -6 says that there are two numbers, one named x and the other named y, such that if we multiply the first one (x) by a negative 4 and add that result to three times the second one (y), we get a sum of a negative 6.
Re: I need a little hand please.
That is all the info I got from this puzzle.
: (
Denis said:What is the question?
Please post original problem in full.
That is all the info I got from this puzzle.
: (
Re: I need a little hand please.
Thank you, I will try that.
Loren said:-4x +3y= -6 says that there are two numbers, one named x and the other named y, such that if we multiply the first one (x) by a negative 4 and add that result to three times the second one (y), we get a sum of a negative 6.
Thank you, I will try that.
Re: I need a little hand please.
If the intent is to solve that equation for y, then start by isolating the term with y (not with x):
3y = 4x - 6
Now divide each term by 3:
y = (4/3)x - 2
That's it. You can't play magician and make x vanish as you did :wink:
That represents a straight line with slope = 4/3 and y-intercept = -2
To understand what that means, go here: http://www.mathsisfun.com/equation_of_line.html
Also, you need to learn how to solve properly; looking at what you did:
-4x +3y= -6
-4x = -6 -3y
X= ( -6 -3y / -4 )
Here, multiply each term in 2nd line by -1; so you get:
4x = 6 + 3y ; now do the division by 4:
x = (6 + 3y) / 4 : the brackets must be the way I'm showing
Here, we've solved the equation for x instead of for y..
To get familiar with solving, go learn here:
http://www.mathsteacher.com.au/year10/c ... /solve.htm
"New" in what way? Are you in school? Learning on your own?maurize said:New at this an trying to understand
-4x +3y= -6
If the intent is to solve that equation for y, then start by isolating the term with y (not with x):
3y = 4x - 6
Now divide each term by 3:
y = (4/3)x - 2
That's it. You can't play magician and make x vanish as you did :wink:
That represents a straight line with slope = 4/3 and y-intercept = -2
To understand what that means, go here: http://www.mathsisfun.com/equation_of_line.html
Also, you need to learn how to solve properly; looking at what you did:
-4x +3y= -6
-4x = -6 -3y
X= ( -6 -3y / -4 )
Here, multiply each term in 2nd line by -1; so you get:
4x = 6 + 3y ; now do the division by 4:
x = (6 + 3y) / 4 : the brackets must be the way I'm showing
Here, we've solved the equation for x instead of for y..
To get familiar with solving, go learn here:
http://www.mathsteacher.com.au/year10/c ... /solve.htm
Re: I need a little hand please.
Thank you kindly, I'm learning on my own.
hugs-
Denis said:"New" in what way? Are you in school? Learning on your own?maurize said:New at this an trying to understand
-4x +3y= -6
If the intent is to solve that equation for y, then start by isolating the term with y (not with x):
3y = 4x - 6
Now divide each term by 3:
y = (4/3)x - 2
That's it. You can't play magician and make x vanish as you did :wink:
That represents a straight line with slope = 4/3 and y-intercept = -2
To understand what that means, go here: http://www.mathsisfun.com/equation_of_line.html
Also, you need to learn how to solve properly; looking at what you did:
-4x +3y= -6
-4x = -6 -3y
X= ( -6 -3y / -4 )
Here, multiply each term in 2nd line by -1; so you get:
4x = 6 + 3y ; now do the division by 4:
x = (6 + 3y) / 4 : the brackets must be the way I'm showing
Here, we've solved the equation for x instead of for y..
To get familiar with solving, go learn here:
http://www.mathsteacher.com.au/year10/c ... /solve.htm
Thank you kindly, I'm learning on my own.
hugs-