I guess its obvious I don't get parabolas

[Guest]

I am sorry for posting so much I am just freaking out at the finals packet we just got.......

so my last 2 quations...for today :lol: ....

1) find the equation in standard form that has the vertex (3,2) and focus ( 3,4)

2) find the equation of the parabola in standard form that has focus (-2,2) and directrix x=4


thanks again everyone

 

[stapel]

You've received the following information in replies to other posts:

Complete the square. [That is, put the equation in the form "y = a(x - h)² + h".]

. . . . .Vertex is V(h,k)

. . . . .Focus is F(h+p,k)

. . . . .Directrix is x=h-p

The standard form of a vertical parabola is x² = 4py, where p is the distance from the vertex to the focus. The directrix is a distance p from the vertex opposite the focus.

How far have you gotten in using this information? Please reply showing what you have tried and clearly stating where you are stuck.

Thank you.

Eliz.

 

[Guest]

well for the first one I have (x-3)^2= 8y-16

and the second one im not sure how to do because i dont know if i am doing the first one right

 

[stapel]

Complete worked solution posted here.