I forgot simple algebraic functions

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We are reviewing some of our work in my trig class and I forgot how to Evaluate the following.


(6a^1/3)^3

Is it just 6a because I am not sure.
 
Carlos said:
We are reviewing some of our work in my trig class and I forgot how to Evaluate the following.


(6a^1/3)^3

Is it just 6a because I am not sure.
Click to expand...


You are nearly there but don't forget that you are also cubing 6


(6a^1/3)^3 =


(6^3)(a^(1/3 x 3) =

216 a ^3/3 =

216a^1 =

216a
 
well uhm I still don't understand why you did that and if so how could I simplify:



(4y^4)^3/2
 
I think I understand what you did

Wait I think I understand. I think my problem is that I am viewing 6a as a number all of its own but I am forgetting that what I do to one I must do to the other. So would


(4y^4)^3/2= (4 * 3/2) (y^4* 3/2)= 8y^6 ?
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