I dont understand synthetic division for polynomial function
- Thread starter kortness
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please help.
D
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You just have to look at the table until you see it.
If x+3 is a factor, then x = -3 is a zero.
Zero
-3
Coeficients
1 -13 -48
You should get these numbers
1
1*(-3) = -3
-13 + (-3) = -13 - 3 = -16
-16*(-3) = 48
-48 + 48 = 0
And we see that \(\displaystyle \frac{x^{2}-13x-48}{x+3}\;=\;x-16\). It's all in the numbers.
If x+3 is a factor, then x = -3 is a zero.
Zero
-3
Coeficients
1 -13 -48
You should get these numbers
1
1*(-3) = -3
-13 + (-3) = -13 - 3 = -16
-16*(-3) = 48
-48 + 48 = 0
And we see that \(\displaystyle \frac{x^{2}-13x-48}{x+3}\;=\;x-16\). It's all in the numbers.