NaNa_Assata
New member
- Joined
- Mar 24, 2011
- Messages
- 1
4x^3+ax^2+bx+c
Local min: -11
Inflection point x=-2
a=?
b=?
c=?
HELP!
Local min: -11
Inflection point x=-2
a=?
b=?
c=?
HELP!
I dont even know where to start....
- Thread starter NaNa_Assata
- Start date
- Joined
- Apr 12, 2005
- Messages
- 11,339
1) Start with proper notatin. Is there a function, here? Maybe, f(x) = 4x^3+ax^2+bx+c
2) You don't know how to find minima and maxima? You should, or you should not have been given this problem.
Local Min: -11. This should suggest that for some value, say x = d, we have f(d) = -11 and (d,-11) is a local minimum.
If (d,11) is a local minimum, then f'(d) = 0 and f"(d) > 0
Inflection Point: x = -2
This hould say to you f"(-2) = 0.
2) You don't know how to find minima and maxima? You should, or you should not have been given this problem.
Local Min: -11. This should suggest that for some value, say x = d, we have f(d) = -11 and (d,-11) is a local minimum.
If (d,11) is a local minimum, then f'(d) = 0 and f"(d) > 0
Inflection Point: x = -2
This hould say to you f"(-2) = 0.