please look at that
E eccsm New member Joined May 14, 2012 Messages 3 May 15, 2012 #1 please look at that Attachments didNotSolve.jpg 5.6 KB · Views: 10 Adsız.jpg 9.9 KB · Views: 6 Last edited: May 15, 2012
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 May 15, 2012 #2 They're tough to read, but for the third one: \(\displaystyle \displaystyle \int\frac{sin2\theta}{sin^{2}\theta+1}d\theta\) Let \(\displaystyle t=sin^{2}\theta+1, \;\ dt=sin2\theta d\theta\)
They're tough to read, but for the third one: \(\displaystyle \displaystyle \int\frac{sin2\theta}{sin^{2}\theta+1}d\theta\) Let \(\displaystyle t=sin^{2}\theta+1, \;\ dt=sin2\theta d\theta\)
E eccsm New member Joined May 14, 2012 Messages 3 May 15, 2012 #3 galactus said: They're tough to read, but for the third one: \(\displaystyle \displaystyle \int\frac{sin2\theta}{sin^{2}\theta+1}d\theta\) Let \(\displaystyle t=sin^{2}\theta+1, \;\ dt=sin2\theta d\theta\) Click to expand... thanks
galactus said: They're tough to read, but for the third one: \(\displaystyle \displaystyle \int\frac{sin2\theta}{sin^{2}\theta+1}d\theta\) Let \(\displaystyle t=sin^{2}\theta+1, \;\ dt=sin2\theta d\theta\) Click to expand... thanks
S srmichael Full Member Joined Oct 25, 2011 Messages 848 May 15, 2012 #4 Hint for d: Let u = lnx What have you tried for a and b?
D Deleted member 4993 Guest May 15, 2012 #5 eccsm said: please look at that Click to expand... Hint for (a) (x-1)(x+1) = x2 -1 continue......
E eccsm New member Joined May 14, 2012 Messages 3 May 15, 2012 #6 thanks thanks for helps ı can solve that now
