You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an alternative browser.
You should upgrade or use an alternative browser.
I cant figure out how to do this problem
- Thread starter bridget2
- Start date
I'm suppose to find the vertex and be able to tell whether the parabola opens up or downIn math today our teacher gave us these worksheets which is based on quadratic functions, but this one equation on this worksheet has me stumped...can someone help please?
the equation is y=2(x-3)2 + 4
I'm suppose to find the vertex and be able to tell whether the parabola opens up or down
I'm quite SURE this is in your textbook (in the future, you might want to remember to look THERE first!!).
The "vertex form" for the equation of a parabola (or quadratic function) is
y = a(x - h)^2 + k
The VERTEX is the point (h, k).
The parabola opens UP if a > 0 and opens DOWN if a < 0.
Here's an example:
y = -2(x - 5)^2 + 3
y = a(x - h)^2 + k
Because a = -2, and that is NEGATIVE, the parabola opens downward. And the vertex is at (5, 3)....see that h = 5 and k = 3?
Now, you see what you can do with your problem!
But the problem is the class called integrated math doesn't have a book. otherwise i would've looked it up first.I'm quite SURE this is in your textbook (in the future, you might want to remember to look THERE first!!).
The "vertex form" for the equation of a parabola (or quadratic function) is
y = a(x - h)^2 + k
The VERTEX is the point (h, k).
The parabola opens UP if a > 0 and opens DOWN if a < 0.
Here's an example:
y = -2(x - 5)^2 + 3
y = a(x - h)^2 + k
Because a = -2, and that is NEGATIVE, the parabola opens downward. And the vertex is at (5, 3)....see that h = 5 and k = 3?
Now, you see what you can do with your problem!