`The vowels, since we are not including y, are "a, e, i, o, u". There are 5 vowels and 21 consonants. You want 8 letters containing exactly 5 vowels and 3 consonants. First, if we write "c" for any consonant and "v" for any vowel, how many different orders are there for "vvvvvccc"? Now there are 5 choices for the first vowel, 4 choices for the second vowel, then three choices for the third, etc. There are 5*4*3*2*1= 5! ways to choose the vowels. There are 21 choices for the first consonant, 20 choices for the second consonant and 19 choices for the third so 21*20*19= 21!/18! ways to choose the consonants.
What reasoning do you have for "dividing the consonants by the vowels"? Have you yet calculated the number of ways you can order "vvvcccccccccc"?
There are 5 vowels and 21 consonants.If a 'word' is interpreted to be a sequence of letters,
how many 8-letter 'words' with no repeated letters contain all five vowels?
(Note: that y is not considered a vowel.)
What question do you have regarding the posted solution? Please be specific. Thank you!If a "word" is interpreted to be a sequence of letters, how many five-letter words with no repeated letters contain two vowels? (Note that y is not considered a vowel.)
I know that the vowels, since we are not including y, are "a, e, i, o, u". There are 5 vowels and 21 consonants. You I want 5 letters containing exactly 2 vowels and 3 consonants. If I write "c" for any consonant and "v" for any vowel, how am I supposed to know how many different orders are there for "vvcccc"?
I've read throughout the entire thread but I'm still not sure what to answer...