I am stuck on the partial fraction pard on the inproper integral
K khansaheb Full Member Joined Apr 6, 2023 Messages 887 Dec 16, 2023 #2 kaizomuninaru said: View attachment 36837 Click to expand... Please show us what you have tried and exactly where you are stuck. Please follow the rules of posting in this forum, as enunciated at: READ BEFORE POSTING Please share your work/thoughts about this problem You do not need to use "partial fractions" to solve this assignment. Last edited: Dec 16, 2023
kaizomuninaru said: View attachment 36837 Click to expand... Please show us what you have tried and exactly where you are stuck. Please follow the rules of posting in this forum, as enunciated at: READ BEFORE POSTING Please share your work/thoughts about this problem You do not need to use "partial fractions" to solve this assignment.
K khansaheb Full Member Joined Apr 6, 2023 Messages 887 Dec 17, 2023 #3 kaizomuninaru said: View attachment 36837 Click to expand... Hint: Substitute (x-3) = u Change the given bounds of integration too - from bounds on x [x=2 & x=3] to bounds on 'u' [u = ? to ??]
kaizomuninaru said: View attachment 36837 Click to expand... Hint: Substitute (x-3) = u Change the given bounds of integration too - from bounds on x [x=2 & x=3] to bounds on 'u' [u = ? to ??]
Steven G Elite Member Joined Dec 30, 2014 Messages 14,561 Dec 21, 2023 #4 You also need to be careful going from x=2 to x=4.