I am stuck on a graphing problem, I don't know how to do it.

[anne]

I have a ti-82 graphing calculator. this is the problem I don't understand how to do:
Use the intersect command on a graphing utility to solve the equation. Round your answer to two decimal places.
5x-27=(4^3)√(-6-2x)
X≈____


So, I am doing this in an online class with 100 other students, and the professor takes too long to respond, otherwise i would have asked him. Do I do this on my calculator making each side of the equation a different line, Y1=5x-27 and Y2=(4^3)√(-6-2x) then seeing where they intersect each other? i tried this for a similar problem and got one line correct but not the line where X was inside the square root Symbol.....

 

[HallsofIvy]

Yes, set up the two functions y1= 5x- 27 and \(\displaystyle y_2= 4^3\sqrt{-6-2x}\). Graph them and see where they intersect. I'm not sure why you have "\(\displaystyle 4^3\)" rather than just "64". As for the square root, you will be have to be careful how you set your window. \(\displaystyle \sqrt{-6- 2x}\) will only return a real value for x< -3.