Hyperbolas - (H,K) form

[Xearf_987]

Greetings!

In my Algebra II class, we are currently studying Hyperbolas. As I was doing my homework, I stumbled across a problem I wasn't quite sure how to do.

How exactly do I put: 4x^2 - y^2 = 0 into (H,K) form so that I can graph the center of the hyperbola?

I understand that on hyperbolic equations, you must first complete the square and then divide each term of the equation by the number on the right side of the equals sign so that the equation equals one.

Please let me know if I have not made myself clear.

I appreciate your help!

 

[Guest]

the general from of a hypebola is
(x-h)^2 (y-k)^2
-------- - --------- =1
a^2 b^2

or
(y-k)^2 (x-h)^2
--------- - --------- =1
a^2 b^2
since the right of yr equation is zero, this is not a hypebola
the left side can be factored as
(2x+y)(2x-y)=0
then solve for y and graph
you'll have 2 lines intersect at the origin for the graph
hope this help