hyperbola question

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Determine an equation in standard form for this hyperbola.

centre (-2,1), one focus (-4,1), length of conjugate axis.


1. What's the conjugate axis? the major of minor axis? x or y axis?
2. I don't get even how they got the answer which is:(x+2)^2/3- (y-1)^2=1
 
anna said:
Determine an equation in standard form for this hyperbola.
centre (-2,1), one focus (-4,1), length of conjugate axis.
1. What's the conjugate axis? the major of minor axis? x or y axis?
2. I don't get even how they got the answer which is:(x+2)^2/3- (y-1)^2=1
Click to expand...
School is over...where did you get this problem?
Why are you given a problem on something you seem to have never
heard of?
If you do not know what the x-axis and y-axis are, you're way over your
head, and need to go back to understanding a simple straight line...
 
I know what an x and y axis, just wondering what a CONJUGATE axis is..and I'm doing summer school that's why I'm asking questions when reg. school is over. I'm upgrading in math.
 
anna said:
I know what an x and y axis, just wondering what a CONJUGATE axis is..and I'm doing summer school that's why I'm asking questions when reg. school is over. I'm upgrading in math.
Click to expand...
I see...keep it up!

Why did you ask what x/y axis were then?
 
oh sry, I must have worded it wrong. I meant whats the conjugate axis, is it the yaxis or the xaxis, I know it's one of them..
 
Hello, anna!

Determine an equation in standard form for this hyperbola.

centre (-2,1), one focus (-4,1), length of conjugate axis . . . missing data ... is it 2 ?

1. What's the conjugate axis? the major of minor axis? x or y axis?
Click to expand...
The conjugate axis is the <u>minor</u> axis.
. . [The major axis is also called the transverse axis.]

Is it vertical or horizontal?
. . It depends on the orientation of the hyperbola.
. . This one has a focus directly to the left of its center.
. . It is a "horizontal" hyperbola: .- ) - ( -


2. I don't get how they got the answer: (x+2)<sup>2</sup>/3 - (y-1)<sup>2</sup> = 1
Click to expand...
The standard form for this hyperbola is:

. . . (x - h)<sup>2</sup> . . (y - k)<sup>2</sup>
. . . --------- - ---------- . = . 1
. . . . . a<sup>2</sup> . . . . . .b<sup>2</sup>

We know that the center is: .(h,k) = (-2,1)

We also know that: .c = 2, .b = 1
. . Since c<sup>2</sup> = a<sup>2</sup> + b<sup>2</sup>, we have: .2<sup>2</sup> = a<sup>2</sup> + 1<sup>2</sup> . . ---> . . a<sup>2</sup> = 3

And that's how they got that answer . . .

[If you didn't understand any of that,
. . you need more work on the <u>basics</u> of conics.]
 
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