simplify: 5w^2 - 80 / w^2 + 2w - 24
K kdreynolds New member Joined Dec 6, 2009 Messages 1 Dec 6, 2009 #1 simplify: 5w^2 - 80 / w^2 + 2w - 24
D Denis Senior Member Joined Feb 17, 2004 Messages 1,707 Dec 6, 2009 #2 Show your work please. Homework not done here.
D Deleted member 4993 Guest Dec 8, 2009 #3 kdreynolds said: simplify: 5w^2 - 80 / w^2 + 2w - 24 Click to expand... And post your problem correctly... as posted your problem is to simplify: \(\displaystyle 5w^2 - \frac{80}{w^2} + 2w - 24\) which could not be "simplified meaningfully". However, if you had posted: Simplify: (5w^2 - 80) / (w^2 + 2w - 24) which would have been equivalent to: \(\displaystyle \frac{5w^2 - 80}{w^2 + 2w - 24}\) this can be simplified meaningfully. As a first step - factorize the numerator and the denominator, and show us where you are stuck.
kdreynolds said: simplify: 5w^2 - 80 / w^2 + 2w - 24 Click to expand... And post your problem correctly... as posted your problem is to simplify: \(\displaystyle 5w^2 - \frac{80}{w^2} + 2w - 24\) which could not be "simplified meaningfully". However, if you had posted: Simplify: (5w^2 - 80) / (w^2 + 2w - 24) which would have been equivalent to: \(\displaystyle \frac{5w^2 - 80}{w^2 + 2w - 24}\) this can be simplified meaningfully. As a first step - factorize the numerator and the denominator, and show us where you are stuck.
