How would I find linear fcn containing (2,-5), (-3.5)?
- Thread starter irishrain
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skeeter
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1. find the slope using the slope formula.
\(\displaystyle \L m = \frac{y_1 - y_2}{x_1 - x_2}\)
2. using the slope found in step 1, and using either point (it doesn't matter which one you use), use the point-slope form of a linear equation to find the equation of the line.
\(\displaystyle \L y - y_1 = m(x - x_1)\)
\(\displaystyle \L m = \frac{y_1 - y_2}{x_1 - x_2}\)
2. using the slope found in step 1, and using either point (it doesn't matter which one you use), use the point-slope form of a linear equation to find the equation of the line.
\(\displaystyle \L y - y_1 = m(x - x_1)\)
Thanks so much for the help!
Yes. That was a typo, sorry.
I meant (2,-5) (-3,5)
I didn't understand exactly what I was supposed to do once I plugged the numbers into the (y-y1)=m(x-x1) formula. I've done it over and over and this is what I get...where's the error?
y+5=-2(x-2)
y+5=-2(x+-4)
y=-2x+1
:x
alexandra
Yes. That was a typo, sorry.
I meant (2,-5) (-3,5)
I didn't understand exactly what I was supposed to do once I plugged the numbers into the (y-y1)=m(x-x1) formula. I've done it over and over and this is what I get...where's the error?
y+5=-2(x-2)
y+5=-2(x+-4)
y=-2x+1
:x
alexandra
stapel said:
After I plugged in the numbers I thought I was supposed to multiply the slope(-2) by
(X1) which is 2. That makes negative 4. Have I got this all mixed up?
y+5=-2(x-2)
y+5=-2(x+-4)
y=-2x+1
I'm using this problem for an example.
(3,1) (2,5)
Slope works out to be -4
y-1=-4(x-3)
y-1=-4x+12
y=-4x+13
Sorry for the trouble, but thank you for the help!
Alexandra
Thanks so much!