how to work in reverse to find f from f' = 6xe^(3x^2)-4/x

[carson_6969]

given:

f'(x)= 6xe^(3x^2) - 4/x

I have to to find the function f(x)

I know the part 4/x is ln 4

this is my guess

x^(6)e^(x^3)- ln 4

dont know really please help!

 

[Deleted member 4993]

Re: how work in reverse?????

given:

f'(x)= 6xe^(3x^2) - 4/x

I have to to find the function f(x)

I know the part 4/x is ln 4 No ... it would be 4*ln(x)

this is my guess

x^(6)e^(x^3)- ln 4 Differentate this .. see if you get back the original function

dont know really please help!

Have you been taught integration?

 

[pka]

What is the derivative of \(\displaystyle e^{3x^2 } - 4\ln (x)\)?

 

[carson_6969]

no we haven't get to integration we still in logs and derivative

 

[pka]

no we haven't get to integration we still in logs and derivative

Well then answer my question to you.