(x2-1+2y)dx + (1-x2)dy = 0 when x=2, y=1
C Carl Geoffrey D. Sanchez New member Joined Apr 25, 2020 Messages 2 Apr 25, 2020 #1 (x2-1+2y)dx + (1-x2)dy = 0 when x=2, y=1
C Carl Geoffrey D. Sanchez New member Joined Apr 25, 2020 Messages 2 Apr 25, 2020 #2 What is the suitable method for solving this ODE? (x2-1+2y)dx + (1-x2)dy = 0 when x=2, y=1 I have tried the common approaches and they do not seem to work.
What is the suitable method for solving this ODE? (x2-1+2y)dx + (1-x2)dy = 0 when x=2, y=1 I have tried the common approaches and they do not seem to work.
D Deleted member 4993 Guest Apr 25, 2020 #3 Carl Geoffrey D. Sanchez said: What is the suitable method for solving this ODE? (x2-1+2y)dx + (1-x2)dy = 0 when x=2, y=1 I have tried the common approaches and they do not seem to work. Click to expand... (x2-1+2y)dx = (x2 - 1)dy dy/dx = (x2-1+2y)/(x2 - 1) dy/dx - y * 2/(x2 - 1) = 1 Now use integrating factor and solve it.
Carl Geoffrey D. Sanchez said: What is the suitable method for solving this ODE? (x2-1+2y)dx + (1-x2)dy = 0 when x=2, y=1 I have tried the common approaches and they do not seem to work. Click to expand... (x2-1+2y)dx = (x2 - 1)dy dy/dx = (x2-1+2y)/(x2 - 1) dy/dx - y * 2/(x2 - 1) = 1 Now use integrating factor and solve it.
