50000x = 2^x
P pappus Junior Member Joined Feb 13, 2012 Messages 220 Apr 8, 2012 #2 connielathrop said: 50000x = 2^x Click to expand... You can't solve this kind of equation algebraically. Use a numerical method (for instance Newton's method) to get an approximate result: 2^x-50000x = 0 Using Newton's method: x_{n+1} = x_n - (2^x_n-50000x_n)/(ln(2) * 2^x_n - 50000) Start with x_1 = 0 or x_1 = 19 to get the two possible values for x.
connielathrop said: 50000x = 2^x Click to expand... You can't solve this kind of equation algebraically. Use a numerical method (for instance Newton's method) to get an approximate result: 2^x-50000x = 0 Using Newton's method: x_{n+1} = x_n - (2^x_n-50000x_n)/(ln(2) * 2^x_n - 50000) Start with x_1 = 0 or x_1 = 19 to get the two possible values for x.
