how to solve for x in logx^4+logx^16+logx^64=1292 ?

rohan009 said:
logx^4+logx^16+logx^64=1292
what is the value of x?
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Is the equation meant to be as follows?

. . . . .\(\displaystyle \log(x^4)\, +\, \log(x^{16})\, +\, \log(x^{64})\, =\, 1,292\)

If not, please provide corrections. If so, what did you get when you applied the log rule for exponents? (here) What did you then get when you combined the "like terms" on the left-hand side? What did you get when you divided through? What did you then get when you applied the relationship between logs and exponentials? ;)
 
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