How to solve for equation

[grapz]

g(x) = 3 + x + e ^ x

what are the x values that g(x) = 4

so i do
4 = 3 + x + e ^ x
1 = x + e ^x


how do i go about solving for x?

 

[Loren]

hint: n^0 = 1 where n ~= 0.

 

[morson]

The solution is the intersection of the curve y = e^x and the straight line y = -x + 1 on the x-y plane. If you are familiar with how both relations look on a graph, you'd know there can only be one solution. It looks like they both intersect on the y-axis, by inspection.

 

[Deleted member 4993]

Plot

y = e^x + x - 1

on your graphical calculator and see where y = 0.

Then justify it by inserting into the equation.

 

[grapz]

Is there a way to do it mathamatically by rearranging and solving for x?

 

[skeeter]

Is there a way to do it mathamatically by rearranging and solving for x?

not by using elementary methods.