How to simplify dy/dx = (-2/(1-x)^2) / (1+x/1-x)

kimmy_koo51 said:
How to simplify dy/dx = (-2/(1-x)^2) / (1+x/1-x)
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Well, 1+x/1-x = 1+x-x = 1. That's certainly simpler. :shock:

You simply MUST be more careful with your notation. Must.
 
sry...I try...I don't have any idea how to do the fancy stuff that other people who post do. Thanks for the help....
 
Hello, kimmy_koo51!

Simplify: \(\displaystyle \L\:\frac{dy}{dx} \:=\:\frac{\frac{-2}{(1\,-\,x)^2}}{\frac{1\,+\,x}{1\,-\,x}}\)
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Multiply top and bottom by \(\displaystyle (1\,-\,x)^2\)

. . \(\displaystyle \L\frac{(1\,-\,x)^2\,\cdot\frac{-2}{(1\,-\,x)^2}} {(1\,-\,x)^2\,\cdot\,\frac{1\,+\,x}{1\,-\,x}} \;=\;\frac{-2}{(1\,-\,x)(1\,+\,x)} \;=\;\frac{-2}{1\,-\,x^2}\)

 
kimmy_koo51 said:
sry...I try...I don't have any idea how to do the fancy stuff that other people who post do. Thanks for the help....
Click to expand...
It's not a matter of "fancy". It's a matter of parentheses and the order of operations. Is it really harder to type (1-x)/(1+x), than it is to type it so that it fails to mean what you want?
 
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