How to integrate with exp in denominator

[medicalphysicsguy]

Hello again, I have a Diff Eq problem to integrate:
\(\displaystyle \int{\frac{1}{exp(-y)+1}dy}\)

I can't figure out the principle. Is it integration by parts somehow?

Thanks

 

[pka]

Hello again, I have a Diff Eq problem to integrate:
\(\displaystyle \int{\frac{1}{exp(-y)+1}dy}\)
I can't figure out the principle. Is it integration by parts somehow?

\(\displaystyle \dfrac{1}{\exp(-y)+1}=\dfrac{\exp(y)}{1+\exp(y)}\)

 

[medicalphysicsguy]

Thanks

Great, thanks.

 

[HallsofIvy]

Or, equivalently, let \(\displaystyle u= e^{-y}+ 1\).