I'm guessing that the given phrase "4 zeros" is supposed to be "4 Real zeros". Each Real zero shows up as an x-intercept; therefore, the graph must cross (or touch) the x-axis at four different places.
In pre-calculus, we learn that polynomial functions of even degree show similar global behavior. That is, the value heads in the same direction (toward either positive infinity or negative infinity), as x gets very big or very small.
This means that the ends of a fourth-degree polynomial graph must both go up or both go down. However, the function in this exercise has an absolute (global) minimum; therefore, the ends of this graph must both go up.
Many different graphs satisfy the given information. That is, the general shape is the same, but the details are different. You get to choose where the x-intercepts are located. You get to choose where to draw the minimums and maximum.
For example, you could draw the graph coming down in Quadrant II, crossing the negative x-axis, continuing down in Quadrant III, turning around and heading back over the x-axis into Quadrant II again.
At this stage, the graph shows two Real zeros and one minimum.
If the graph now turns and heads down over the x-axis and returns up a second time, there will be four x-intercepts, one maximum, and two minimums. Finish by drawing the right end of the graph heading up in Quadrant I.
Make sure that the two minimums are not at the same level. One of them must be lower (the absolute minimum).
If you need more help, please ask specific questions. If I wrote anything that you don't understand, then that's what you should ask about next.