How to graph this function?

TheNascar92

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Sep 14, 2009
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18
I have the function of:

F(x)=-x^3+4x^2-8 (it reads negative x cubed plus 4 x squared minus 8- sorry dont know how to type superscripts)

I am supposed to find the zeros of this function and graph it but im very lost. I used synthetic division and found (x-2) to be a factor and 2 as a zero but with the quotient I cannot do anything else I have tried the quadratic formula which produces imaginary zeros (I need to graph on a coordinate plane) and I cannot factor this. If anyone has any clue as to how to find the remaining zeros your help is much appreciated. Thanks in advance.

Kimberly
 
TheNascar92 said:
F(x) = -x^3 + 4x^2 - 8 … sorry dont know how to type superscripts …

Your typing shows that you do know how to type the exponents; we use the caret symbol ^, just like you did.

However, your typing shows that you do not know how to type an apostrophe. :wink:


… I have tried the quadratic formula [with the quotient] which produces imaginary zeros …


Hi Kimberly:

Either you divided wrongly, and your quadratic quotient is wrong, OR you make a mistake using the Quadratic Formula.

F(x) has three Real zeros.

Try again, and if you cannot find your mistake(s), then please post your work.

Cheers ~ Mark 8-)

 
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