TheNascar92
New member
- Joined
- Sep 14, 2009
- Messages
- 18
I have the function of:
F(x)=-x^3+4x^2-8 (it reads negative x cubed plus 4 x squared minus 8- sorry dont know how to type superscripts)
I am supposed to find the zeros of this function and graph it but im very lost. I used synthetic division and found (x-2) to be a factor and 2 as a zero but with the quotient I cannot do anything else I have tried the quadratic formula which produces imaginary zeros (I need to graph on a coordinate plane) and I cannot factor this. If anyone has any clue as to how to find the remaining zeros your help is much appreciated. Thanks in advance.
Kimberly
F(x)=-x^3+4x^2-8 (it reads negative x cubed plus 4 x squared minus 8- sorry dont know how to type superscripts)
I am supposed to find the zeros of this function and graph it but im very lost. I used synthetic division and found (x-2) to be a factor and 2 as a zero but with the quotient I cannot do anything else I have tried the quadratic formula which produces imaginary zeros (I need to graph on a coordinate plane) and I cannot factor this. If anyone has any clue as to how to find the remaining zeros your help is much appreciated. Thanks in advance.
Kimberly