how to go from u_{n+1} - u_n = 3((u_n)^2 - u_n) + 1 to 3(u_n - 1/2)^2 + 1/4 ?

Shuai

New member
Joined
Jun 11, 2016
Messages
2
Hello

I have something like this :
png.latex

Can someone explain to me how they went from
png.latex
TO
png.latex

Thank you very much
 
I have something like this:

. . . . .\(\displaystyle u_{n+1}\, -\, u_n\, =\, 3\, \left(u_n^2\, -\, u_n\right)\, +\, 1\, =\, 3\, \left(u_n\, -\, \dfrac{1}{2}\right)^2\, +\, \dfrac{1}{4}\)

Can someone explain to me how they went from

. . . . .\(\displaystyle 3\, \left(u_n^2\, -\, u_n\right)\, +\, 1\)

to

. . . . .\(\displaystyle 3\, \left(u_n\, -\, \dfrac{1}{2}\right)^2\, +\, \dfrac{1}{4}\)
What did you get, when you completed the square? (here) ;)
 
Top