how to find the square root of 225x to the third power

[daszy]

i dont understand how to find the square root of 225x to the third power

 

[skeeter]

\(\displaystyle \L \sqrt{225x^3} = \sqrt{15^2 \cdot x^2 \cdot x} = \sqrt{15^2}\sqrt{x^2}\sqrt{x} = 15|x|\sqrt{x}\)

 

[daszy]

thanks!

 

[tkhunny]

Always a dispute.

In this case, the absolute values are not necessary.

Additional information in the original expression and in the final expression, namely \(\displaystyle \sqrt{x}\), already restricts to \(\displaystyle x \ge 0\).