abel muroi
Junior Member
- Joined
- Jan 13, 2015
- Messages
- 210
I was given this problem...
What is the minimum value of f(x) = (x + 3)2 - 5 defined for all real x.
A. x = -5
B. x = -3
C. x = 4
D. Not defined
I'm not sure if i did this correctly, but i used all the answers and plugged them in for x in the original equation, and -3 was the minimum value
x = -3
f(x) = (x + 3)2 - 5
f(x) = (-3 + 3)2 - 5
f(x) = (0)2 - 5
f(x) = 0 - 5
f(x) = -5
This is the method that I used to get my answer, which is B
Is B the right answer, or did I miss something?
What is the minimum value of f(x) = (x + 3)2 - 5 defined for all real x.
A. x = -5
B. x = -3
C. x = 4
D. Not defined
I'm not sure if i did this correctly, but i used all the answers and plugged them in for x in the original equation, and -3 was the minimum value
x = -3
f(x) = (x + 3)2 - 5
f(x) = (-3 + 3)2 - 5
f(x) = (0)2 - 5
f(x) = 0 - 5
f(x) = -5
This is the method that I used to get my answer, which is B
Is B the right answer, or did I miss something?