How to find standard form of ?????

[hil]

Hello, the vertex is (-2, -4) I decieded to use (-1,-2) as the points. Im looking to find standard,transformational, and general form. I must say standard form confuses me, lol a thorough explanation would be appreciated! Am I correct in thinking
y=a(x+2)^2-4
:?-2+4=a(-1+2)^2-4+4
:?2=a1 then dividing a1 by 2 and getting 1/2 or is it 0.5?

 

[akoaysigod]

I'm not even sure what you're asking. But I'm going to guess that you have some function, line, graph thing, etc. whose vertex is at (-2, -4).

If you're equation is x^2. To put it's vertex at (-2, -4) you'd have to add in the y direction, up and down, -2. Then x^2 - 2.

In the y direction, adding or subtracting to the function will move it up and down, respectively.

Now for the right/left, or x direction you have to add to the variable. In this case, (x+4)^2, will move it left, or negatively. And subtracting will move it positively. Which is confusing at first but it's something you'll memorize.

Otherwise I don't really know what you're asking and you should try to be more clear. =(