how to factor this, i am dying ): please help someone!

[mathsam]

4x^3 -6x^2 +12x

 

[burakaltr]

4x^3 -6x^2 +12x

Factor x out and get
x*(4x**2-6x+12)

for the 4x**2-6x+12



apply delta= b**2 - 4 *a *c

to get delta = 36-192 = - 156

it has three roots which are 0, an imaginary root and conjugate

 

[lookagain]

Factor x out and get
x*(4x**2-6x+12)

for the 4x**2-6x+12

burakaltr,

please use "^" for exponentiatio instead of **:

x(4x^2 - 6x + 12)


(Also, there is no need for the multiplication asterisk
between x and (4x^2 - 6x + 12).



--------------------------------------------------------------


mathsam,

this is a recommendation:

Factor out the greatest common factor of the expression,
which is 2x, before proceeding:


\(\displaystyle 2x(2x^2 - 3x + 6)\)



*** Edit: I had the g.c.f wrong as 2; it is 2x.

 

[burakaltr]

burakaltr,

please use "^" for exponentiatio instead of **:

x(4x^2 - 6x + 12)


(Also, there is no need for the multiplication asterisk
between x and (4x^2 - 6x + 12).



--------------------------------------------------------------


mathsam,

this is a recommendation:

Factor out the greatest common factor of the expression,
which is 2, before proceeding:


\(\displaystyle 2(2x^2 - 3x + 6)\)

Sorry Sir

I was using FORTRAN notation.

 

[lookagain]

Please note the edit made in my last post regarding the
greatest common factor. Thank you.