Where does one begin to solve the equation 3log(x)=6-2x?
C crazylum New member Joined Apr 12, 2008 Messages 10 May 18, 2008 #1 Where does one begin to solve the equation 3log(x)=6-2x?
skeeter Elite Member Joined Dec 15, 2005 Messages 3,218 May 18, 2008 #2 Re: how to begin? get out your graphing calculator ... graph the equation y = 3log(x) - (6 - 2x) and locate the roots. this equation cannot be solved using elementary algebraic methods.
Re: how to begin? get out your graphing calculator ... graph the equation y = 3log(x) - (6 - 2x) and locate the roots. this equation cannot be solved using elementary algebraic methods.
D Deleted member 4993 Guest May 18, 2008 #3 Re: how to begin? crazylum said: Where does one begin to solve the equation 3log(x)=6-2x? Click to expand... You could use numerical method such as "Newton-Raphson" iteration to estimate the roots of this function. However, graphing and rough-estimating first is very useful - for fast convergence, possible number of solutions(roots) and accuracy of estimation.
Re: how to begin? crazylum said: Where does one begin to solve the equation 3log(x)=6-2x? Click to expand... You could use numerical method such as "Newton-Raphson" iteration to estimate the roots of this function. However, graphing and rough-estimating first is very useful - for fast convergence, possible number of solutions(roots) and accuracy of estimation.