A sum of 1400 dollars is deposited in an account with an interest rate of r percent per year, compunded daily. At the end of 6 years, the balance in the account is given by
\(\displaystyle A=1400\left( 1+\dfrac {r} {36500}\right) ^{2190}\)
Find the rate of change of A with respect to r if the interest rate is r%.
I know that the following is the answer, and it looks like the power rule was used, but that isn't the case. How the heck did it end up at 84, and nothing inside the brackets changed? I also don't understand what the question is asking (find rate of change of A with respect to r). Any help would be greatly appreciated as always!
\(\displaystyle A=84\left( 1+\dfrac {r} {36500}\right) ^{2189}\)
\(\displaystyle A=1400\left( 1+\dfrac {r} {36500}\right) ^{2190}\)
Find the rate of change of A with respect to r if the interest rate is r%.
I know that the following is the answer, and it looks like the power rule was used, but that isn't the case. How the heck did it end up at 84, and nothing inside the brackets changed? I also don't understand what the question is asking (find rate of change of A with respect to r). Any help would be greatly appreciated as always!
\(\displaystyle A=84\left( 1+\dfrac {r} {36500}\right) ^{2189}\)