How should i interprete that kind of input?

akwardcy

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Mar 5, 2020
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(dx/dt)/(dy/dt)=x/y
? Assuming i'm nobody in that kind of equations ?
 
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I am not sure what do you mean by that.

Are you trying to say - you have NO WORK to share?

Where did you come upon this equation?
Just learning my mechanics stuff and thought about it like it came from nothing so I wonder if there is someone who can explain me where to find answer for where to start looking for it.
 
I think this is just a joke. It is posted under "differential equations" but is really a fairly straight forward Integral Calculus problem. And when asked what he does understand about the problem or what he has done on it awkwardcy just gives snarky responses!
 
I think this is just a joke. It is posted under "differential equations" but is really a fairly straight forward Integral Calculus problem. And when asked what he does understand about the problem or what he has done on it awkwardcy just gives snarky responses!
I really not trolling just thinking intensly bout nubers ratio their powers and their functions but today morning i get with this and didn't know how to deal with this
 
I think this is just a joke. It is posted under "differential equations" but is really a fairly straight forward Integral Calculus problem. And when asked what he does understand about the problem or what he has done on it awkwardcy just gives snarky responses!
Sir. I'm not lazy potatoe
 
Where i can find meaning of your worlds beacuseim just after Mathematical analysis 1 and only heard a bit but diffrential equations for now
 
Sir. I'm not lazy potatoe
I never suggested you were lazy (and the correct spelling is "potato"), I suggested that you were intentionally writing things you knew were nonsense. Your response "Actually i thought either about bit diffrent things before" is completely meaningless. It tells us nothing about what you do understand about this equation and what you have tried already.

In any case, if you have taken Calculus you should recognize that \(\displaystyle \frac{\frac{dx}{dt}}{\frac{dy}{dt}}= \frac{dx}{dy}\)
so that your equation is \(\displaystyle \frac{dx}{dy}= \frac{x}{y}\).

And that can be "separated" as \(\displaystyle \frac{dx}{x}= \frac{dy}{y}\) and each side integrated separately.
 
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