How do you solve this equation?

[sigma]

How do you solve this equation if you have a transpose in the variable your solving for? How do you un-transpose the variable C so you can solve for it? Just do it, then transpose everything on the RHS? Not sure. This equation needs to be solved for C.

\(\displaystyle \
\L\
2A + C^T = B{\rm } \to {\rm }C^T = B - 2A
\\)

 

[galactus]

Just transpose the other side.

\(\displaystyle \L\\C=(B-2A)^{T}\)

 

[sigma]

That's what I figured. Thanks!