how do you do this?

[arthistorygeek]

:?:

i have no idea what this means.

"Find (f [than a little "o" like thing, not filled in like a multplication dot] g)(4) for each pair of functions."

f(x) = -2x[squared], g(x) 4x+1

 

[skeeter]

\(\displaystyle \L (f \circ g)(x) = f[g(x)]\)

this is called function composition ... putting one function "inside" of another.

if \(\displaystyle \L f(x) = -2x^2\), and \(\displaystyle \L g(x) = 4x + 1\),

then \(\displaystyle \L f[g(x)] = f(4x+1) = -2(4x+1)^2\)

and

\(\displaystyle \L f[g(4)] = -2(4*4 + 1)^2 = -578\)

 

[arthistorygeek]

Im still confused. Could you explain it more in words instead of numbers and variables?

 

[galactus]

Art History?. Why not major in something more worthwhile, like Ancient Babylonian Astrology. :lol:

I'm sorry, I couldn't help it. Don't be mad at me.:lol:

 

[ctess]

Ok you basicly take the value of g(x) and stick it inside of f(x).

thats basicly what he said:

so say:

g(x) = 2

and you have the problem: (F o G)(x)

Well you would set it up like:

f[g(x)]

because you are putting the value in the place of x within the f(x) function.

so with the example above it would look like:

F(2)

 

[arthistorygeek]

gracias

Thankyouthankyouthankyou ctess!

poop on babylonian astrology....JK!

 

[skeeter]

read more about it ...
function composition

Art History?. Why not major in something more worthwhile, like Ancient Babylonian Astrology.

... or ancient Sumerian religions? "There is no Dana, only Zool."