How do you do it O.o? Please help, test tomorrow!

[Marvelous Things]

How am I able to figure this out using geometry?

EDIT: Oh and E is in the center. I just forgot to put it there.

 

[Gene]

Just so you won't feel ignored...
Are you saying B bisects arc ABC or D bisects arc ADC or both?
Is the center E the intersection of AC and BD? (I have trouble with pictures on my ISP.) If so, AC is a diameter which makes it too easy 'cause AE = EC = 6?
If you give the length of AD, I can't make out what it is.
------------------
Gene

 

[Coraelle]

Here you go..

E is the intersection point of AC and DB

BD bisects Arc AC

Line AC has length of 6

Either Arc AD or Line AD has length 8.. you need to specify though, or we can't help.

 

[Marvelous Things]

Sorry, that length of AD = 8

 

[Gene]

That still leaves open whether B bisects arc ABC or D bisects arc ADC or both?
And do you agree with Coraelle that AC = 6?? I took it as AE = 6. Do you really mean E is the center of the circle as well as the intersection.

 

[Marvelous Things]

I am going to draw another better one.

AD=8

AE=6

DC=12

DB bisects ARC ABC....does that help?

 

[Denis]

OK...how in heck did you expect any help from your 1st diagram :evil:

 

[Gene]

Since it was due today I'll give you what I got.
Call angle AED P
Call EC x
Call angle ADB D
ADB=BDC=D from the bisection.
From the law of sines
6/sin(D) = 8/sin(P) so
1/sin(D) = 8/(6sin(P)

x/sin(D) = 12/sin(pi-P)
8x/6sin(P)= 12/sin(P)
8x/6=12
x=9

EC = 9