How do I work this out on a Cas calculator?

Devilish symptoms

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Could anyone break this down for me please so I can work out the answer?

A golf ball is hit from bunker.
H = 5.2t =1.5t(squared) -1
The (squared was meant to be a little 2)
H = height
T = time

a) how deep is bunker
b) when is the ball at first level the top of the bunker
c) at which times is the ball of 3m
d) max height
e) how longs it in the air

If someone could possibly break this down for me I'd really appreciate it.

Thanks!
 
Can anyone break this down for me please so I can work out the answer?

A golf ball is hit from bunker.
H = 5.2t =1.5t(squared) -1
The (squared was meant to be a little 2)
H = height
T = time

a) how deep is bunker
b) when is the ball at first level the top of the bunker
c) at which times is the ball of 3m
d) max height
e) how longs it in the air

If someone could possibly break this down for me I'd really appreciate it.

Thanks

Unfortunately, in all your resends, you didn't proofread. This doesn't make sense! A few other things aren't quite what was probably written.

Possibly the equation was H = 5.2t - 1.5t2 - 1 , which I'd normally write as H = -1.5t2 + 5.2t - 1.

Now, if you read the READ BEFORE POSTING notice, or the summary here, you know that we want you not only to state the entire problem (accurately), but also to show us where you need help. That allows us to give the answer you need, not the answer someone else might need.

The first thing to do will be to figure out the meaning of the questions. Do you know what a bunker is? (If not, search for "bunker in golf".) The idea is that the shot STARTS below ground level. (I would have hoped the problem would explicitly say that H is the height above ground, and that the ground is level. But we have to assume that.)

At what height does the ball start? (That is, what is H at time t=0?)

Then take each of the other questions and think about what it means in terms of t and H.

I imagine you must have learned about finding the vertex (highest or lowest point) of a parabola, as well as how to evaluate a function and how to solve for t given a particular value of H. All those things will come into play.

Please show us what you CAN do, and tell us what help you need.
 
Could anyone break this down for me please so I can work out the answer?
You say that you want to do the work, but I don't know what kind of guidance you have in mind. Have you pondered anything, yet? Are you stuck at a particular point? :cool:




H = 5.2t =1.5t(squared) -1
The (squared was meant to be a little 2)
H = height
T = time
We use the caret symbol ^ to show exponents. Like this:

H = 5.2*t - 1.5*t^2 - 1

:idea: T and t are two different symbols. It's best to use one or the other (we don't need both, for the same quantity). Also, there's a link in the forum guidelines, for learning how to type math expressions using a keyboard, if you'd like to take a look.




If someone could possibly break this down for me I'd really appreciate it.
Please explain the type of breakdown you have in mind. ;)

I'll start with:

Symbols H and t are variables; their values change continuously, during the ball's trip through air. These symbols represent measurements of "Height" (H) and "elapsed time" (t).

In this exercise, "Height" is the vertical distance between the ball and ground level. (This vertical measurement is also what we call a 'directed distance' because sometimes it's positive and sometimes it's negative.) When the ball is below ground level (i.e., it's in the bunker), we measure H downward from ground level, and H becomes a negative number. When the ball is above ground level, we measure H upward, and its a positive number. When the ball is at ground level, H is zero. I'm assuming that H is measured in feet and t is measured in seconds, so here's one example of H and t values: 1/10th of a second after the ball is hit, the ball is vertically located 0.495 feet below ground level. Therefore, H=-0.495 when t=0.1

H and t each have a beginning value (the instant the ball is hit and the clock starts measuring time). They each have an ending value (the instant the ball hits the ground and the clock stops measuring t).

The quantities H and t have a fixed relationship; at any instant, if you know one of these quantities, you can find the other, by using substitution in the given formula for H.

H = 5.2*t - 1.5*t^2 - 1
 
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