How do I solve this Quadratic Equation?

[bobcat89]

28.100= 1/4 ( y² +1993.562- ((y+87.39)²)/5 )

I am having issues trying to solve this equation.

When I decide to expand it, the y²cancels out; as in y² - y²=0
And if I square the entire (-(y+87.39))², it becomes a complex eqn

So I am at a loss and yet the solutions given are 15.922[FONT=Arial, Helvetica, Arial, sans-serif] & [/FONT]27.773.

Please help!

 

[Deleted member 4993]

28.100= 1/4 ( y² +1993.562- ((y+87.39)²)/5 )

I am having issues trying to solve this equation.

When I decide to expand it, the y²cancels out; as in y² - y²=0
And if I square the entire (-(y+87.39))², it becomes a complex eqn

So I am at a loss and yet the solutions given are 15.922 & 27.773.

Please help!

Does your problem look like this:

\(\displaystyle 28.100 \ = \ \dfrac{1}{4} \ * \ \left [y^2 \ - \ 1993.562 \ - \ \dfrac{(y+87.39)^2}{5} \right ]\)

If it is, then y²s do not cancel out and you have to deal with those hideous numbers! But the resulting equation, after expansion of the square term, would be still quadratic equation (with superbly ugly constant coefficients!).

 

[bobcat89]

Does your problem look like this:

\(\displaystyle 28.100 \ = \ \dfrac{1}{4} \ * \ \left [y^2 \ - \ 1993.562 \ - \ \dfrac{(y+87.39)^2}{5} \right ]\)

If it is, then y²s do not cancel out and you have to deal with those hideous numbers! But the resulting equation, after expansion of the square term, would be still quadratic equation (with superbly ugly constant coefficients!).

Thank you! That actually makes it a lot clearer!