The drawing shows a person looking at a building on top of which an antenna is mounted. The horizontal distance between the person's eyes and the building is L = 86.1 m. In part (a) the person is looking at the base of the antenna, and his line of sight makes an angle of θa = 39.0° with the horizontal. In part (b) the person is looking at the top of the antenna, and his line of sight makes an angle of θb = 41.3° with the horizontal. How tall is the antenna?
How do I figure this out?
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Dr.Peterson
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Can you define a variable or two, then find right triangles and write equations for them?
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Draw a diagram.
Let [MATH]P[/MATH] be position of the person's eyes and let [MATH]Q[/MATH] be the point on the antenna horizontal with the person's eyes. Let [MATH]R[/MATH] be the top and [MATH]S[/MATH] the base of the antenna. You should now be able to identify two right-angled triangles that can be solved to help you find the answer you require.
Let [MATH]P[/MATH] be position of the person's eyes and let [MATH]Q[/MATH] be the point on the antenna horizontal with the person's eyes. Let [MATH]R[/MATH] be the top and [MATH]S[/MATH] the base of the antenna. You should now be able to identify two right-angled triangles that can be solved to help you find the answer you require.