How do I do this problem?

moronatmath

Junior Member
Joined
Feb 14, 2006
Messages
83
Soroban gave me the walkthrough (which I will be studying)

Please delete this post admin.

Thank you soroban!
 
What have you done on this problem?
What do you think the answer could be?
Show us some effort on your part!
 
(h,k) are the coordinates for the vertex. (x,y) is the point it passes

through. Use the standard form of a parabola:

\(\displaystyle y=a(x-h)^{2}+k\)

Sub in your information, solve for a, then you pretty much have it.
 
y=(a)(7-(-2)^2+7

y=(a)(9)^2+7
y=(a) 81+7
y=(a) 88
and than I am stuck :(
Could you tell me were I went wrong please?
 
moronatmath said:
y=(a)(7-(-2)^2+7
There is an unmatched parenthesis, but I think you mean the following:

. . . . .y = (a)[7 - (-2)]<sup>2</sup> + 7

However, as was pointed out, the vertex values get plugged in for "h" and "k". You need to substitute properly: the h-value goes in for "h", the k-value goes in for "k", the x-value (from the provided point) goes in for "x", and the y-value goes in for "y". Then solve for "a".

moronatmath said:
y=(a) 81+7
y=(a) 88
You might want to review "order of operations" which says, among other things, that multiplication comes before addition, so, if "81" had been correct, it should have multiplied by the "a" before the "7" was added in.

Eliz.
 
88=(a)[7 - (-2)]^2 + 7

So divide [7 - (-2)]^2 first?

88/[7 - (-2)]^2=a+7

simplify?

(88)/(7)-(-2)^2=60/7

60/7= a+7
subtract 7

a=11/7 ???

I get incorrect? Can you please show me how this problem is done? I am about ready to give up :(
 
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