How do I find n in the equation: (1.005)^(-36n) _____________ = 0.21475206 (0.99)^(-4n)
D d1zzy07 New member Joined Oct 1, 2010 Messages 2 Oct 1, 2010 #1 How do I find n in the equation: (1.005)^(-36n) _____________ = 0.21475206 (0.99)^(-4n)
mmm4444bot Super Moderator Joined Oct 6, 2005 Messages 10,962 Oct 1, 2010 #2 You could start by multiplying both sides of the given equation by: (0.99)^(-4n)/0.21475206 Then, after applying some properties of logarithms and factoring, the resulting equation becomes: 4n * [9 ln(1.005) - ln(0.99)] = -ln(0.21475206) You can solve this equation for n, yes? I welcome specific questions. Cheers ~ Mark
You could start by multiplying both sides of the given equation by: (0.99)^(-4n)/0.21475206 Then, after applying some properties of logarithms and factoring, the resulting equation becomes: 4n * [9 ln(1.005) - ln(0.99)] = -ln(0.21475206) You can solve this equation for n, yes? I welcome specific questions. Cheers ~ Mark