How can I solve this parametric equation (p-1) *x^2 - (p-2) *x + (2*p -1) = 0?

robkio

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We are learning complex numbers and this equation has something with it.
 
How do you solve this parametric equation (p-1) *x^2 - (p-2) *x + (2*p -1) = 0?

[h=1]How do you solve this parametric equation (p-1) *x^2 - (p-2) *x + (2*p -1) = 0 and it has something to do with complex numbers?[/h]
 
How do you solve this parametric equation (p-1) *x^2 - (p-2) *x + (2*p -1) = 0 and it has something to do with complex numbers?
You have one equation in two variables. This cannot be solved algebraically.

Please reply with the full and exact text of the exercise, the complete instructions, and any other relevant information (such as why you think this equation "has something to do with complex numbers"). Thank you! ;)
 
Sorry but this is everything what i have. We have learned complex numbers and then we got this equation
 
Sorry it's not parametric equation but quadratic equation with parameter
 
How do you solve this parametric equation (p-1) *x^2 - (p-2) *x + (2*p -1) = 0 and it has something to do with complex numbers?
Sorry it's not parametric equation but quadratic equation with parameter

What are your thoughts?

Please share your work with us ...even if you know it is wrong

If you are stuck at the beginning tell us and we'll start with the definitions.

You need to read the rules of this forum. Please read the post titled "
Read before Posting" at the following URL:

http://www.freemathhelp.com/forum/th...Before-Posting
 
this is everything what i have.
If the exercise had no instructions, then there is no way to know what is wanted, and thus no way to find "the answer".

We have learned complex numbers and then we got this equation
So, before you worked with complex numbers at all (adding, multiplying, simplifying, etc), you were given this equation with no directions as to what to do with it?

I think i need to find the solution for negative discriminant
What has led you to conclude that this might be with the (missing) instructions (would have) said?

it's not parametric equation but quadratic equation with parameter
Since this is one equation in two unknowns, there is no way to solve the equation for anything numerical. If perhaps there had been instructions that said something like "find the values of p for which the discriminant is always negative, so that all solution values of x are complex", then we might possibly be able to advise. But this is a lot of guessing.

Please ask your instructor to provide the missing instructions, so that we all can know what is expected of you. Thank you! ;)
 
Yes I need to find p so that the discriminant is negative. Thank you
 
Yes I need to find p so that the discriminant [of (p-1) *x^2 - (p-2) *x + (2*p -1) = 0] is negative.
Okay; so you learned (back before complex numbers) about the Quadratic Formula (here) and its discriminant, b2 - 4ac. In this case, a = p - 1, b = -(p - 2), and c = 2p - 1. You plugged these into the formula for the discriminant, set the expression "less than zero", and... then what?

Please be complete. Thank you! ;)
 
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