You have one equation in two variables. This cannot be solved algebraically.How do you solve this parametric equation (p-1) *x^2 - (p-2) *x + (2*p -1) = 0 and it has something to do with complex numbers?
How do you solve this parametric equation (p-1) *x^2 - (p-2) *x + (2*p -1) = 0 and it has something to do with complex numbers?
If the exercise had no instructions, then there is no way to know what is wanted, and thus no way to find "the answer".this is everything what i have.
So, before you worked with complex numbers at all (adding, multiplying, simplifying, etc), you were given this equation with no directions as to what to do with it?We have learned complex numbers and then we got this equation
What has led you to conclude that this might be with the (missing) instructions (would have) said?I think i need to find the solution for negative discriminant
Since this is one equation in two unknowns, there is no way to solve the equation for anything numerical. If perhaps there had been instructions that said something like "find the values of p for which the discriminant is always negative, so that all solution values of x are complex", then we might possibly be able to advise. But this is a lot of guessing.it's not parametric equation but quadratic equation with parameter
Sorry but this is everything what i have. We have learned complex numbers and then we got this equation
Okay; so you learned (back before complex numbers) about the Quadratic Formula (here) and its discriminant, b2 - 4ac. In this case, a = p - 1, b = -(p - 2), and c = 2p - 1. You plugged these into the formula for the discriminant, set the expression "less than zero", and... then what?Yes I need to find p so that the discriminant [of (p-1) *x^2 - (p-2) *x + (2*p -1) = 0] is negative.