How can I prove the convergence of this series? Thank you !
M MAV New member Joined Apr 9, 2020 Messages 4 Apr 9, 2020 #1 How can I prove the convergence of this series? Thank you ! Attachments serie.png 47.2 KB · Views: 5
topsquark Senior Member Joined Aug 27, 2012 Messages 2,393 Apr 9, 2020 #2 You might start with writing out an expression that can be read more easily. Is it [math]\sum_{m = 1}^{ \infty } \dfrac{ sin(m) ~ sin( m^2 ) }{2m^2 + 1} (x - 1)^{2m}[/math] That doesn't look right to me. I would imaging you are looking for the "radius of convergence?" -Dan
You might start with writing out an expression that can be read more easily. Is it [math]\sum_{m = 1}^{ \infty } \dfrac{ sin(m) ~ sin( m^2 ) }{2m^2 + 1} (x - 1)^{2m}[/math] That doesn't look right to me. I would imaging you are looking for the "radius of convergence?" -Dan
M MAV New member Joined Apr 9, 2020 Messages 4 Apr 9, 2020 #3 topsquark said: You might start with writing out an expression that can be read more easily. Is it [math]\sum_{m = 1}^{ \infty } \dfrac{ sin(m) ~ sin( m^2 ) }{2m^2 + 1} (x - 1)^{2m}[/math] That doesn't look right to me. I would imaging you are looking for the "radius of convergence?" -Dan Click to expand...
topsquark said: You might start with writing out an expression that can be read more easily. Is it [math]\sum_{m = 1}^{ \infty } \dfrac{ sin(m) ~ sin( m^2 ) }{2m^2 + 1} (x - 1)^{2m}[/math] That doesn't look right to me. I would imaging you are looking for the "radius of convergence?" -Dan Click to expand...