House placement

[jm1gic]

Good morning, I am picking a point on my land to place a house. to the get plans approved I need to tell measurements. I am trying to save myself a trip out there to just measure the distance. I think I have it simplified though.

I have a right triangle, The right angle measurements are 150ft and 56.11 ft. the hypotenuse is 160.55ft.

Ok, i think this will help clear it up.. but at the same time make it more confusing. Hopefully it doesn't!

Basically, looking at this picture, can you tell me how many feet line a and line b are?

hopefully it helps!

 

[Deleted member 4993]

Good morning, I am picking a point on my land to place a house. to the get plans approved I need to tell measurements. I am trying to save myself a trip out there to just measure the distance. I think I have it simplified though.

I have a right triangle, The right angle measurements are (a) 150ft and (b) 56.11 ft. the hypotenuse is (c) 160.55ft.

If I pick a point on line (a) and draw it straight to the hypotenuse, how do I know the distance from A to C... Example.

Starting from one side, i pick a point that is 40 ft in on line A, I draw a line straight to line C (160.55). Because of the angle I wouldn't be able to say that it is 40 ft from the edge on the hypotenuse, it should be more. How do I figure out how much more?

Does that make sense?

First draw the original right triangle - draw the points A and C.

Please post the sketch - as discussed above - and explain your work referring to the sketch.

 

[jm1gic]

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First draw the original right triangle - draw the points A and C.

Please post the sketch - as discussed above - and explain your work referring to the sketch.

ok awesome, I just updated my original post. hopefully my attempt to make it less confusing doesn't make it more confusing

Actually to add to the confusion. it turns out I can't edit for a 2nd time, so i'm actually needing this A and B.. I moved them when compared to the new image., I got to pre occupied with that other lengths

 

[Deleted member 4993]

First draw the original right triangle - draw the points A and C.

Please post the sketch - as discussed above - and explain your work referring to the sketch.

You have:

RP = 160.5, PQ = 150, QP = 150, PN = 67.5, QT = 43.5

You can calculate MP = b

Using similar triangles PQR and PMN

PM/PR = PN/PQ

PM/160.55 = 67.5/150

PM = ?

Now calculate

RS = a ........................ again using proportionality properties in similar triangles.