Horizontal Asymptotes

jesusphreek82

New member
Joined
Apr 5, 2006
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6
I dont understand how to find horizontal Asymptotes .... can anyone help me with this problem??

y= (x-3)/(x-2)

this is due tomorrow.... I really need help! I would appreciate it :lol:
 
Hello, jesusphreek82!

Find horizontal asymptote: \(\displaystyle \,\L y\:=\:\frac{x\,-\,3}{x\,-\,2}\)
We want to know what happens to \(\displaystyle y\) as \(\displaystyle x\) get very very large
. . . either positively or negatively.

That is, does \(\displaystyle \lim_{x\to\infty} y\) have a finite value?

\(\displaystyle \;\;\)Does \(\displaystyle \;\lim_{x\to\infty}\left(\frac{x\,-\,3}{x\,+\,3}\right)\) have a limit?


"Eyeballing" it, it seems to go to \(\displaystyle \frac{\infty}{\infty}\) . . . which is no help.


Here's the "trick": divide top and bottom by \(\displaystyle x:\) **

\(\displaystyle \L\;\;\lim_{x\to\infty}\left(\frac{\frac{x}{x}\,-\,\frac{3}{x}}{\frac{x}{x}\,+\,\frac{3}{x}}\right) \;=\;\lim_{x\to\infty}\left(\frac{1\,-\,\frac{3}{x}}{1\,+\,\frac{3}{x}}\right) \;=\;\frac{1\,-\,0}{1\,+\,0}\;=\;1\)


We have shown that, as \(\displaystyle x\to\infty,\;y\) approaches \(\displaystyle 1.\)

Therefore, the horizontal asymptote is: \(\displaystyle \,y\,=\,1\)

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** \(\displaystyle \;\)Rule

Divide top and bottom by the highest power of \(\displaystyle x\) in the denominator
 
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